Remove Specific Namespace from XML

Recently, I needed to come up with a solution to remove a namespace from a scala.xml.Node. I couldn't find anything online that would solves this specific problem. I found some help removing all namespaces from the Node, and built my solution off of that (http://stackoverflow.com/questions/12535014/scala-completely-remove-namespace-from-xml)

But I wanted to share my code to remove a specified namespace incase this helps someone out there trying to do the same thing.

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This Snippet of XML rewriting code will loop through all of the Nodes within a given Node. On each of the XML Elements it will take the namespace you want removed and: - remove entire elements that are prefixed with the attribute - remove attributes that are prefixed with the namespace - remove the namespace from the scope of the XML Element

This will result in the following transformation:
<foo xmlns:xoox="http://example.com/xoox" xmlns:keep="http://example.com/keep"> <baz xoox:asd="first" keep:dsa="green">123</baz> <xoox:baz xoox:asd="second">456</xoox:baz> <keep:baz keep:dsa="blue">789</keep:baz> <baz>10</baz> </foo>

<foo xmlns:keep="http://example.com/keep"> <baz keep:dsa="green" xmlns:keep="http://example.com/keep">123</baz> <keep:baz keep:dsa="blue">789</keep:baz> <baz>10</baz> </foo>

When used like this:
val transformed = new RuleTransformer(new RemoveNamespace("xoox")).transform(document).head

Where document is the input scala.xml.Node and transformed is the resulting scala.xml.Node